(2x+3)^=3+(4x+3)

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Solution for (2x+3)^=3+(4x+3) equation: 



(2x+3)^=3+(4x+3)

We move all terms to the left:

(2x+3)^-(3+(4x+3))=0



We calculate terms in parentheses: -(3+(4x+3)), so:

3+(4x+3)

determiningTheFunctionDomain
(4x+3)+3

We get rid of parentheses

4x+3+3

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

(2x+3)^-4x-6=0

We add all the numbers together, and all the variables

-4x+(2x+3)^-6=0

We move all terms containing x to the left, all other terms to the right

-4x+(2x+3)^=6

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